How do you solve #(3x - 1) ( 4x - 3) = 0#?

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Answer 1 · 2017-08-01T21:28:46

See a solution process below:

To solve this equate each term on the left side of the equation to #0# and solve for #x#:

Solution 1

#3x - 1 = 0#

#3x - 1 + color(red)(1) = 0 + color(red)(1)#

#3x - 0 = 1#

#3x = 1#

#(3x)/color(red)(3) = 1/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 1/3#

#x = 1/3#

Solution 2

#4x - 3 = 0#

#4x - 3 + color(red)(3) = 0 + color(red)(3)#

#4x - 0 = 3#

#4x = 3#

#(4x)/color(red)(4) = 3/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = 3/4#

#x = 3/4#

The Solutions Are: #x = 1/3# and #x = 3/4#