How do you solve #-3x + 1= - 8#?

1 Answer
Jim G.
Feb 1, 2017

#x=3#

Explanation:

Isolate - 3x on the left side by subtracting 1 from both sides of the equation.

#-3xcancel(+1)cancel(-1)=-8-1#

#rArr-3x=-9#

To solve for x, divide both sides by - 3

#(cancel(-3) x)/cancel(-3)=(-9)/(-3)#

#rArrx=3#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if this is equal to the right side then it is the solution.

#"left side "=(-3xx3)+1=-9+1=-8color(white)(xx)✔︎#

#rArrx=3" is the solution"#

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