Question

How do you solve `-3x + 1= - 8`?

Answer 1

`x=3`

Explanation:

Isolate - 3x on the left side by subtracting 1 from both sides of the equation.

`-3xcancel(+1)cancel(-1)=-8-1`

`rArr-3x=-9`

To solve for x, divide both sides by - 3

`(cancel(-3) x)/cancel(-3)=(-9)/(-3)`

`rArrx=3`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if this is equal to the right side then it is the solution.

`"left side "=(-3xx3)+1=-9+1=-8color(white)(xx)✔︎`

`rArrx=3" is the solution"`