How do you solve #-3x + 1= - 8#?
1 Answer
Feb 1, 2017
Explanation:
Isolate - 3x on the left side by subtracting 1 from both sides of the equation.
#-3xcancel(+1)cancel(-1)=-8-1#
#rArr-3x=-9# To solve for x, divide both sides by - 3
#(cancel(-3) x)/cancel(-3)=(-9)/(-3)#
#rArrx=3#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if this is equal to the right side then it is the solution.
#"left side "=(-3xx3)+1=-9+1=-8color(white)(xx)✔︎#
#rArrx=3" is the solution"#