How do you solve #(3x - 1) ( x - 7) = 0#?

1 Answer
Alan P.
Oct 31, 2016

#x=1/3# or #x=7#

Explanation:

Remember that if #color(red)(axxb=0)# then either #color(blue)(a=0)# or #color(blue)(b=0)#

Therefore if #color(red)((3x-1)(x-7)=0#
#color(white)("XX"){:(color(blue)(3x-1=0),color(white)("XX")orcolor(white)("XX"),color(blue)(x-7=0)), (color(blue)(rarr x=1/3),,color(blue)(rarr x=7)) :}#

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