Question

How do you solve `3x+14=38-5x`?

Answer 1

`x=3`

Explanation:

Collect the terms in x to the left side of the equation and numeric values to the right side.

add 5x to both sides.

`3x+5x+14=38cancel(-5x)cancel(+5x)`

`rArr8x+14=38`

subtract 14 from both sides.

`8xcancel(+14)cancel(-14)=38-14`

`rArr8x=24`

To solve for x, divide both sides by 8.

`(cancel(8) x)/cancel(8)=24/8`

`rArrx=3" is the solution"`