How do you solve #3x - 2< 2x + 3#?

1 Answer
MeneerNask
Oct 27, 2016

In an inequality you may add or subtract at will, without the sign changing.

Explanation:

Subtract #2x# from both sides:
#3x-2x-2< cancel(2x)-cancel(2x)+3->x-2<3#

Now add #2# to both sides:
#x+cancel2-cancel2<3+2->x<5##

Related questions
Impact of this question
518 views around the world
You can reuse this answer
Creative Commons License