How do you solve $3x + 2(5x + 4) = 47$ ?

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Answer 1 · 2018-05-02T16:45:22

$x=3$

Firstly, multiply out the brackets to simplify:

$3x+2(5x+4)=47$
$3x+10x+8=47$

Then rearrange to place all like-terms on one side to simplify:

$13x+8=47$
$13x=47-8$
$13x=39$
$x=39/13$
$x=3$

So when the value of $x$ is substituted into the original equation, you should get the solution of $47$ :

$3x+2(5x+4)=47$
$3(3)+2(5(3)+4)=47$
$9+2(15+4)=47$
$9+30+8=47$

How do you solve 3x + 2(5x + 4) = 473x + 2(5x + 4) = 47?