How do you solve $3 x - 2 (5 x - 4) = 4 x - (2 x - 26)$ $3x - 2( 5x - 4) = 4x - ( 2x - 26)$ ?

Question

781 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-21T02:42:58

$x = - 2$ $x=-2$

Refer to the explanation for the process.

Solve:

$3 x - 2 (5 x - 4) = 4 x - (2 x - 26)$ $3x-2(5x-4)=4x-(2x-26)$

Expand the left side.

$3 x - 10 x + 8 = 4 x - (2 x - 26)$ $3x-10x+8=4x-(2x-26)$

Expand the right side.

$3 x - 10 x + 8 = 4 x - 2 x + 26$ $3x-10x+8=4x-2x+26$

Simplify.

$- 7 x + 8 = 2 x + 26$ $-7x+8=2x+26$

Subtract $2 x$ $2x$ from both sides.

$- 7 x - 2 x + 8 = 26$ $-7x-2x+8=26$

Subtract $8$ $8$ from both sides.

$- 7 x - 2 x = 26 - 8$ $-7x-2x=26-8$

Simplify.

$- 9 x = 18$ $-9x=18$

Divide both sides by $- 9$ $-9$ .

$x = \frac{18}{- 9}$ $x=18/(-9)$

Simplify.

$x = - 2$ $x=-2$

How do you solve 3x−2(5x−4)=4x−(2x−26)3x - 2( 5x - 4) = 4x - ( 2x - 26)?