How do you solve 3x^2+7x-13=0?

1 Answer
Jan 22, 2017

color(blue)x=color(blue)((-7 +sqrt(205))/6 and color(green)(x=(-7 -sqrt(205))/6

Explanation:

This is a quadratic equation with respect to x. We will use the quadratic formula:

For an equation of the type
color(purple)(ax^2 + bx + c = 0, color(red)(a!=0)

x=-b pmsqrt(b^2 -4ac)/(2a)
Putting our values in the equation:

x= -7 pmsqrt((7)^2-4(3)(-13))/(2(3))
x= -7pmsqrt(49+156)/6

=> color(magenta)(x=color(magenta)((-7 pmsqrt(205))/6