# How do you solve 3x + 2\leq 5x + 12?

Nov 17, 2017

$x \ge - 5$

#### Explanation:

First, we need to put the "like terms" on a side of the equation. This means that all the stuff with "x"s on them go on one side, and all the numbers go on the other.

The original inequality was:
$3 x + 2 \le 5 x + 12$

Let's put all the "x" numbers on the left and numbers on the right:
$- 2 x \le 10$

Now this is the tricky part. We have to divide both sides by -2 to get the final answer; however, when you divide by a NEGATIVE SIGN in an inequality, the sign becomes the OPPOSITE. The opposite sign of $\le$ is $\ge$.

$x \ge - 5$