How do you solve #3x + 2\leq 5x + 12#?

1 Answer
Nov 17, 2017

#x >= -5#

Explanation:

First, we need to put the "like terms" on a side of the equation. This means that all the stuff with "x"s on them go on one side, and all the numbers go on the other.

The original inequality was:
#3x + 2 <= 5x + 12#

Let's put all the "x" numbers on the left and numbers on the right:
#-2x <= 10#

Now this is the tricky part. We have to divide both sides by -2 to get the final answer; however, when you divide by a NEGATIVE SIGN in an inequality, the sign becomes the OPPOSITE. The opposite sign of #<=# is #>=#.

So now answer is this:
#x >= -5#