How do you solve #3x^2-x-2 < 0#?

1 Answer
Jim G.
Apr 30, 2018

#-2/3< x <1#

Explanation:

#"factor the quadratic"#

#(x-1)(3x+2)<0#

#"solve "(x-1)(3x+2)=0#

#x-1=0rArrx=1#

#3x+2=0rArrx=-2/3#

#"the coefficient of "x^2" term" >0rArruuu#

#rArr-2/3< x < 1#
graph{3x^2-x-2 [-10, 10, -5, 5]}

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