How do you solve $3x + 2( x + 3) = 4( x - 2) + 4$ ?

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Answer 1 · 2017-11-08T16:51:18

$x = -10$

$3x + 2(x+3) = 4(x-2) + 4$

expand the brackets,

$3x + 2x + 6 = 4x - 8 + 4$

and then solve for x,

$5x +6 = 4x-4$
$x=-10$

How do you solve 3x + 2( x + 3) = 4( x - 2) + 43x + 2( x + 3) = 4( x - 2) + 4?