First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:
#-3x - color(red)(2)(x + 5) = 35#
#-3x - (color(red)(2) xx x) - (color(red)(2) xx 5) = 35#
#-3x - 2x - 10 = 35#
#(-3 - 2)x - 10 = 35#
#-5x - 10 = 35#
Next, add #color(red)(10)# to each side of the equation to isolate the #x# term while keeping the equation balanced:
#-5x - 10 + color(red)(10) = 35 + color(red)(10)#
#-5x - 0 = 45#
#-5x = 45#
Now, divide each side of the equation by #color(red)(-5)# to solve for #x# while keeping the equation balanced:
#(-5x)/color(red)(-5) = 45/color(red)(-5)#
#(color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5)) = -9#
#x = -9#