How do you solve #- 3x - 2( x + 5) = 35#?

1 Answer
May 27, 2017

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#-3x - color(red)(2)(x + 5) = 35#

#-3x - (color(red)(2) xx x) - (color(red)(2) xx 5) = 35#

#-3x - 2x - 10 = 35#

#(-3 - 2)x - 10 = 35#

#-5x - 10 = 35#

Next, add #color(red)(10)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-5x - 10 + color(red)(10) = 35 + color(red)(10)#

#-5x - 0 = 45#

#-5x = 45#

Now, divide each side of the equation by #color(red)(-5)# to solve for #x# while keeping the equation balanced:

#(-5x)/color(red)(-5) = 45/color(red)(-5)#

#(color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5)) = -9#

#x = -9#