Question

How do you solve `-3x + 32< 47`?

Answer 1

`x > -5`

Explanation:

You transpose the constant to the their side so the number with the variable will be left.

`-3x<47-32`

When you transpose, always change the sign of the constant that you transposed. Do the subtracting and after that, divided by both sides by `-3` so `x` will be left.

`(-3x)/-3>15/-3`

Cancel `-3` on the left because they are equal to `1`. Divide `15` by `-3` so you get `-5.`

However, when you multiply or divide an inequality by a negative number, the inequality sign changes around

`cancel((-3)x)/cancel(-3)> cancel15^-5/cancel(-3)^1`

`x > -5`

When you divide a negative number, make sure to flip the less than sign to a greater than sign.

`x > -5` is the answer

Answer 2

`x> - 5`

Explanation:

`-3x+32<47`

`=>-3x<47-32`

`=> -3x<15`
`=>x>15/-3` {because if we send the (-) sign by multiplication or by division to the other side the sign changes to (+).....}

`=>x> -5`

hence the value of `x` is `> -5`