How do you solve $- 3 x + 4 > - 11$ $-3x + 4> - 11$ ?

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Answer 1 · 2016-11-13T20:58:40

$x < 5$ $x < 5$

Begin to isolate $x$ $x$ by subtracting $4$ $4$ on both sides of the inequality

$- 3 x > - 15$ $-3x > -15$

Isolate $x$ $x$ by dividing both sides of the inequality by $- 3$ $-3$

*Remember: When dividing and inequality by a negative, the sign flips

$x < 5$ $x < 5$

How do you solve -3x + 4> - 11−3x+4>−11-3x + 4> - 11?