How do you solve #(3x - 4)/(5) = 7#?

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Answer 1 · 2018-05-05T01:56:36

#x=13#

Given: #(3x-4)/5=7#.

Multiply both sides by #5# to get rid of #5# on the #"LHS"#.

#3x-4=5*7#

#=35#

Add #4# to both sides.

#3x=35+4#

#=39#

Divide by #3# to isolate #x#.

#x=39/3#

#=13#