How do you solve $3 x - 4 < - 8$ $3x-4<-8$ ?

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Answer 1 · 2016-09-24T20:32:13

$x < - \frac{4}{3}$ $x < - 4/3$

Add $4$ $4$ to both sides

$3 x < - 4$ $3x < -4$

Divide by $3$ $3$

$x < - \frac{4}{3}$ $x < - 4/3$

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