How do you solve 3x + 4x + 10- 7= 40?

1 Answer
CW
Oct 29, 2016

3x+4x+10-7=40
(3x+4x)+(10-7)=40
7x+3=40
subtract 3 from both sides :
=> 7x+3-3=40-3
=> 7x=37
divide both sides by 7
=> (cancel7x)/cancel7=37/7

Hence, x=37/7

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