How do you solve 3x +4y = 15 and 3x + 2y = 12?

Jun 8, 2018

$x = 3 , y = \frac{3}{2}$

Explanation:

Multiplying the second equation by$- 1$ and adding to the first we get
$2 y = 3$ so $y = \frac{3}{2}$
plugging this in the second equation

$3 x + 3 = 12$
so
$3 x = 9$
$x = 3$