How do you solve #3x + 5y = 25# and #- 3x - 4y = - 23#?

1 Answer
Mar 4, 2017

# x=7.5" , "y=1/2#

Explanation:

#3x+5y=25" (1)"#
#-3x-4y=-23" (2)"#

#"let us add the equations above to eliminate value x" #

#3x+5y-3x-4y=25-23#

#cancel(3x)+5ycancel(-3x)-4y=25-23#

#5y-4y=25-23#

#4y=2#

#y=2/4#

#color(red)(y=1/2)#

#3x+5y=25" (1)"#

#3x+5*color(red)(1/2)=25#

#3x=25-5/2#

#3x=color(green)(2/2)*25-5/2#

#3x=50/2-5/2#

#3x=(50-5)/2#

#3x=45/2#

#"if "color(blue)(a/b=c/ d)" then "color(blue)(a*d=b*c)#

#(3x)/1=45/2#

#3x*2=1*45#

#6x=45#

#(6x)/(6)=(45)/6#

#(cancel(6)x)/(cancel(6))=(45)/6#

#x=45/6#

#x=7.5#