How do you solve #3x - ( 8- 3x + 3) = 19+ x#?

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Answer 1 · 2018-04-08T13:06:27

#x=6#

#3x-(8-3x+3)=19+x#

By order of operations, work within the braces first:

#3x-(11-3x)=19+x# (Distribute - to the numbers inside the braces)

#3x-11+3x=19+x# (Combine like terms)

#6x-11=19+x# (Subtract x from both sides)

#5x-11=19# (Add 11 to both sides)

#5x=30# (Divide both sides by 5)

#x=6#

Check the answer by plugging it into the original equation:

#3(6)-(11-3(6))=19+6#
#18-(-7)=25#
#18+7=25#
#25=25#