# How do you solve 3x - ( 8- 3x + 3) = 19+ x?

Apr 8, 2018

$x = 6$

#### Explanation:

$3 x - \left(8 - 3 x + 3\right) = 19 + x$

By order of operations, work within the braces first:

$3 x - \left(11 - 3 x\right) = 19 + x$ (Distribute - to the numbers inside the braces)

$3 x - 11 + 3 x = 19 + x$ (Combine like terms)

$6 x - 11 = 19 + x$ (Subtract x from both sides)

$5 x - 11 = 19$ (Add 11 to both sides)

$5 x = 30$ (Divide both sides by 5)

$x = 6$

Check the answer by plugging it into the original equation:

$3 \left(6\right) - \left(11 - 3 \left(6\right)\right) = 19 + 6$
$18 - \left(- 7\right) = 25$
$18 + 7 = 25$
$25 = 25$