How do you solve #3x ^ { \frac { 4} { 3} } - 7= 41#?

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Answer 1 · 2017-07-31T09:25:50

#x=8#

#3x^(4/3)-7=41#

we need to isolate the term in #x#

first add 7 to both sides

#3x^(4/3)cancel(-7color(blue)(+7))=41color(blue)(+7)#

#3x^(4/3)=48#

divide both sides by #3#

#cancel(3/3)x^(4/3)=cancel(48/3)^16#

#x^(4/3)=16#

now we deal with the powers

#x^(4/3)=16#

#=>x=16^(3/4)#

#x=root(4)(16)^3#

#x=2^3#

#x=8#