How do you solve $3x \geq 2( x - 3)$ ?

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Answer 1 · 2017-10-24T02:21:43

$x >= -6$

First, we need to distribute the right part of the equation:

$3x >= 2(x - 3)$

$3x >= 2x - 6$ (distribute the 2 to everything in the parenthesis)

$x >= -6$ (minus 2x on both sides of the equation)

How do you solve 3x \geq 2( x - 3)3x \geq 2( x - 3)?