How do you solve #3x \geq - 9# ?

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Answer 1 · 2017-12-11T13:26:45

#x>= -3#

#"isolate x by dividing both sides by "3#

#(cancel(3) x)/cancel(3)>=(-9)/3#

#rArrx>= -3" is the solution"#

Answer 2 · 2017-12-11T15:01:19

#color(blue)(rArr x >= -3)#

We are given the inequality:

#color(red)(3x >= -9)#

#rArr((3x)/3) >= (-9/3)#

#rArr((cancel(3)x)/cancel 3) >= (-(cancel 3 xx 3)/cancel 3)#

#color(blue)(rArr x >= -3)#

Please investigate the graph below to verify results:

enter image source here