How do you solve #3y + \frac { 1} { 4} = \frac { 13} { 4}#?

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Answer 1 · 2017-07-11T02:13:42

#y=1#

#3y+1/4=13/4#

Multiply all terms by #4# to remove fractions.

#(4xx3y)+(4xx1/4)=(4xx13/4)#

#12y+(1cancel4xx1/(1cancel4))=(1cancel4xx13/(1cancel4))#

#12y+1=13#

Subtract #1# from both sides.

#12y+1-1=13-1#

#12y=12#

Divide both sides by #12#.

#(12y)/12=12/12#

#(1cancel12y)/(1cancel12)=(1cancel12)/(1cancel12)#

#y=1#