How do you solve #4( - 2+ 6x ) = - 152#?

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Answer 1 · 2016-11-28T04:01:29

#x = -6#

First, expand the terms in parenthesisL

#(4*-2) + (4*6x) = -152#

#-8 + 24x = -152#

Now solve for #x# while keeping the equation balanced using the necessary mathematics:

#-8 + 24x + 8 = -152 + 8#

#24x = -144#

#(24x)/24 = -144/24#

#x = -6#