How do you solve #4( 2- v ) = 2v + 2#?

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Answer 1 · 2017-03-25T04:18:08

#1=v#

Steps:

Distribute the #4# to #(2-v) -> 8-4v#

Isolate the variable:

#8cancel(-4v+4v)=2v+4v+2 ->8=6v+2#

#8-2=6v+cancel(2-2) ->6=6v#

#6/6=cancel(6/6)v#

#1=v#

Verify the solution by substituting #1# into #v#

#4(2-1)=2(1)+2#

#4(1)=2+2#

#4=4#