How do you solve #-4( 3- 6k ) - 5= 127#?

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Answer 1 · 2016-11-19T13:19:17

#k = 6#

Step 1) Expand the terms within parenthesis:

#(-4*3) + (-4*-6k) - 5 = 127#

#-12 + 24k - 5 = 127#

Step 2) Combine like terms:

#24k - 12 - 5 = 127#

#24k - 17 = 127#

Step 3) Solve for #k# while keeping the equation balanced:

#24k - 17 + 17 = 127 + 17#

#24k = 144#

#(24k)/24 = 144/24#

#k = 6#