How do you solve #-4(3-x)=2(x+6)#?

1 Answer
Apr 4, 2018

#x = 12#

Here's how I did it:

Explanation:

#-4(3-x) = 2(x+6)#

First, we can divide both sides by #2#:
#-2(3-x) = x+6#

To solve this, we use the distributive property. This means that we "distribute" whatever is outside of the parenthesis to everything inside it:
#-6+2x = x+6#

Now we can subtract #x# from both sides of the equation:
#-6 + x = 6#

Then we add #6# to both sides of the equation:
#x = 12#

Hope this helps!