How do you solve ${4.3}^{x} < 76.2$ $4.3^x<76.2$ ?

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Answer 1 · 2016-12-01T08:44:18

$x < \frac{ln 76.2}{ln 4.3} ≅ 2.97$ $x < ln 76.2/ln 4.3~=2.97$

You can solve the equivalent inequality:

$x < {log}_{4.3} 76.2$ $x < log_4.3 76.2$

or

$x < \frac{ln 76.2}{ln 4.3} ≅ 2.97$ $x < ln 76.2/ln 4.3~=2.97$

How do you solve 4.3x<76.24.3^x<76.2?