How do you solve #4(3x-1.2)=9.5x+6.2#?

1 Answer
Feb 7, 2017

See the entire solution process below:

Explanation:

First, expand the term within parenthesis on the left side of the equation:

#(4 xx 3x) - (4 xx 1.2) = 9.5x + 6.2#

#12x - 4.8 = 9.5x + 6.2#

Next, add #color(red)(4.8)# and subtract #color(blue)(9.5x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#12x - 4.8 + color(red)(4.8) - color(blue)(9.5x) = 9.5x + 6.2 + color(red)(4.8) - color(blue)(9.5x)#

#12x - color(blue)(9.5x) - 4.8 + color(red)(4.8) = 9.5x - color(blue)(9.5x) + 6.2 + color(red)(4.8)#

#2.5x - 0 = 0 + 11#

#2.5x = 11#

Now, divide each side of the equation by #color(red)(2.5)# to solve for #x# while keeping the equation balanced:

#(2.5x)/color(red)(2.5) = 11/color(red)(2.5)#

#(color(red)(cancel(color(black)(2.5)))x)/cancel(color(red)(2.5)) = 4.4#

#x = 4.4#