How do you solve #4^ { 3x } = 4^ { 2( x + 7) }#?

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Answer 1 · 2017-07-20T12:08:01

Solution : #x=14#

# 4^(3x)= 4^(2(x+7) # , bases are equal i.e #4# , so indices will also

be equal , # :. 3x = 2(x+7) or 3x = 2x +14 or x =14#

Check # 4^(3*14)= 4^(2(14+7)# or

#4^42 = 4^42# (checked)

Solution : #x=14# [Ans]

Answer 2 · 2017-07-20T12:34:34

#x=14#

#"since the bases are equal, both 4 then we can equate the"#
#"exponents"#

#rArr3x=2x+14#

#rArrx=14" is the solution"#