How do you solve #-4/3x+9>17#?
1 Answer
May 9, 2018
Explanation:
#"isolate "-4/3x" by subtracting 9 from both sides of the "#
#"inequality"#
#-4/3xcancel(+9)cancel(-9)>17-9#
#rArr-4/3x>8#
#"multiply both sides by 3"#
#rArr-4x>24#
#"divide both sides by "-4#
#color(blue)"noting to reverse the sign as a consequence"#
#rArrx < -6" is the solution"#
#x in(-oo,6)larrcolor(blue)"in interval notation"#
