How do you solve #4^(5n)>30#?

1 Answer
May 19, 2018

Answer:

#n>0.49#

Explanation:

By rules of logarithms:

#lna^b=blna#

Therefore, take the logarithm from both sides of the function and follow the rule. Then proceed to rearrange and simplify to find the solution for #n#.

#ln4^5n>ln30#

#5nln4>ln30#

#5n>ln30/ln4#

#n>(ln30/ln4)/5#

#n>0.49#

Hope this helps!