How do you solve #4( 9+ x ) = 132#?

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Answer 1 · 2017-10-09T10:46:11

See a solution process below:

First, divide each side of the equation by #color(red)(4)# to eliminate the need for parenthesis while keeping the equation balanced:

#(4(9 + x))/color(red)(4) = 132/color(red)(4)#

#(color(red)(cancel(color(black)(4)))(9 + x))/cancel(color(red)(4)) = 33#

#9 + x = 33#

Now, subtract #color(red)(9)# from each side of the equation to solve for #x# while keeping the equation balanced:

#-color(red)(9) + 9 + x = -color(red)(9) + 33#

#0 + x = 24#

#x = 24#