How do you solve #4/9( y + 3) = g#?

1 Answer
smendyka
Sep 3, 2017

See a solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(9)/color(blue)(4)# to eliminate the need for parenthesis while keeping the equation balanced:

#color(red)(9)/color(blue)(4) xx 4/9(y + 3) = color(red)(9)/color(blue)(4) xx g#

#cancel(color(red)(9))/cancel(color(blue)(4)) xx color(blue)(cancel(color(black)(4)))/color(red)(cancel(color(black)(9)))(y + 3) = 9/4g#

#y + 3 = 9/4g#

Now, subtract #color(red)(3)# from each side of the equation to solve for #y# while keeping the equation balanced:

#y + 3 - color(red)(3) = 9/4g - color(red)(3)#

#y + 0 = 9/4g - 3#

#y = 9/4g - 3#

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