# How do you solve -4= \frac { 2} { 4} + b?

Dec 5, 2017

See a solution process below:

#### Explanation:

First, multiply each side of the equation by $\textcolor{red}{2}$ to eliminate the fraction while keeping the equation balanced:

$\textcolor{red}{2} \times - 4 = \textcolor{red}{2} \left(\frac{2}{4} + b\right)$

$- 8 = \left(\textcolor{red}{2} \times \frac{2}{4}\right) + \left(\textcolor{red}{2} \times b\right)$

$- 8 = \frac{4}{4} + 2 b$

$- 8 = 1 + 2 b$

Next, subtract $\textcolor{red}{1}$ from each side of the equation to isolate the $b$ term while keeping the equation balanced:

$- 8 - \textcolor{red}{1} = 1 - \textcolor{red}{1} + 2 b$

$- 9 = 0 + 2 b$

$- 9 = 2 b$

Now, divide each side of the equation by $\textcolor{red}{2}$ to solve for $b$ while keeping the equation balanced:

$- \frac{9}{\textcolor{red}{2}} = \frac{2 b}{\textcolor{red}{2}}$

$- \frac{9}{2} = \frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} b}{\cancel{\textcolor{red}{2}}}$

$- \frac{9}{2} = b$

$b = - \frac{9}{2}$