How do you solve #4> \frac { s } { 3} + 2#?

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Answer 1 · 2018-01-27T14:18:20

See a solution process below:

First, subtract #color(red)(2)# from each side of the inequality to isolate the #s# term while keeping the inequality balanced:

#4 - color(red)(2) > s/3 + 2 - color(red)(2)#

#2 > s/3 + 0#

#2 > s/3#

Now, multiply each side of the inequality by #color(red)(3)# to solve for #s# while keeping the inequality balanced:

#color(red)(3) xx 2 > color(red)(3) xx s/3#

#6 > cancel(color(red)(3)) xx s/color(red)(cancel(color(black)(3)))#

#6 > s#

We can reverse or "flip" the entire inequality to state the solution in terms of #s#:

#s < 6#