# How do you solve 4\leq 3- 2x < 15?

Jun 22, 2017

See below.

#### Explanation:

We take the left part of the inequality first.

$4 \setminus \le q 3 - 2 x$

$1 \setminus \le q - 2 x$

$2 x \setminus \le q - 1$

$x \setminus \le q - \frac{1}{2}$

Now for the right part:

3−2x<15

$- 2 x < 12$

$x > - 6$

But $x \setminus \le q - \frac{1}{2}$, so the range of values $x$ can take is $\left(- 6 , - \frac{1}{2}\right]$.