How do you solve #4\leq 3- 2x < 15#?

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Answer 1 · 2017-06-22T14:52:32

See below.

We take the left part of the inequality first.

#4\leq3-2x#

#1\leq-2x#

#2x\leq-1#

#x\leq-1/2#

Now for the right part:

#3−2x<15#

#-2x<12#

#x> -6#

But #x\leq-1/2#, so the range of values #x# can take is #(-6,-1/2]#.