How do you solve #4( n + 4) = 48#?

2 Answers
Jul 12, 2018

Divide by 4

#n+4=12#

Subtract 4

#n=8#

Jul 12, 2018

Answer:

#n=8#

Explanation:

We start with
#\color(red)(4)(n+4)=48#

Divide by 4 to cancel multiplication:
#(\cancel(\color(red)(4))(n+4))/\cancel(\color(red)(4))=48/\color(red)(4)#
#n+\color(blue)(4)=12#

Subtract 4 to cancel addition:
#n\cancel(+\color(blue)(4))\cancel(-\color(blue)(4))=12-\color(blue)(4)#
#n=8#

You have successfully isolated your variable, solving for its value :-)