How do you solve #4(p+6)+8(p-5)=7-8p+p-4#?

Question

631 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-10T14:37:49

#p=1#

#4(p+6)+8(p-5)=7-8p+p-4#

#4*p+4*6+8*p-8*5=3-7p#

#4p+24+8p-40=3-7p#

#12p-16=3-7p#

#12p+7p=3+16#

#19p=19#

#(cancel(19)p)/cancel(19)=19/19#

#p=1#