How do you solve #-4( v + 1) = 2v - 8+ 2( 4v + 7)#?

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Answer 1 · 2017-06-23T01:18:39

#v=-5/7#

#-4(v+1)=2v-8+2(4v+7)#

The first step is to use the distributive property to get rid of the parentheses.

#-4(v)-4(1)=2v-8+2(4v)+2(7)#

#-4v-4=2v-8+8v+14#

Next, combine like terms.

#-4v-4=10v+6#

Your goal is to isolate #v#, so you can do this by subtracting #10v# on both sides.

#-14v-4=6#

Now you need to move all the constants to the other side. Add #4# on both sides.

#-14v=10#

Last, all you have to do is divide #-14# on both sides to completely isolate #v#!

#v=-10/14#

Don't forget to write your fraction in simplest form.

#v=-5/7#