How do you solve #4( x - 1) - 5x \geq - 2#?

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Answer 1 · 2016-11-19T13:42:01

#x <= -2#

Step 1) Expand the terms within parenthesis:

#(4*x) - (4*1) - 5x >= -2#

#4x - 4 - 5x >= -2#

Step 2) Combine like terms:

#(4 - 5)x - 4 >= -2#

#-x - 4 >= -2#

Step 3) Solve for #x# while keeping the inequality balanced:

#-x - 4 + 4 >= -2 + 4#

#-x >= 2#

#-x*-1 <= 2*-1# We need to reverse the inequality because we are multiplying each side by a negative number.

#x <= -2#