How do you solve #4(x+2) = 4 +x +2#?

2 Answers
Sahar Mulla ❤
Jan 30, 2018

#4(x+2)=4+x+2#

#4x+8=6+x#

#4x-x=6-8#

#3x=-2#

#x=-2/3#

Verification:-

#4((-2/3)+2)=4+(-2/3)+2#

#(-8/3)+8=6+(-2/3)#

#-8+24=18-2#

#16=16#

hence LHS=RHS.

-Sahar.

Jim G.
Jan 30, 2018

#x=-2/3#

Explanation:

#"distribute the bracket and simplify right side"#

#rArr4x+8=6+x#

#"subtract x from both sides"#

#4x-x+8=6cancel(+x)cancel(-x)#

#rArr3x+8=6#

#"subtract 8 from both sides"#

#3xcancel(+8)cancel(-8)=6-8#

#rArr3x=-2#

#"divide both sides by 3"#

#(cancel(3) x)/cancel(3)=(-2)/3#

#rArrx=-2/3" is the solution"#

Related questions
Impact of this question
1185 views around the world
You can reuse this answer
Creative Commons License