How do you solve 4(x+2) = 4 +x +24(x+2)=4+x+2?

2 Answers
Sahar Mulla ❤
Jan 30, 2018

4(x+2)=4+x+24(x+2)=4+x+2

4x+8=6+x4x+8=6+x

4x-x=6-84x−x=6−8

3x=-23x=−2

x=-2/3x=−23

Verification:-

4((-2/3)+2)=4+(-2/3)+24((−23)+2)=4+(−23)+2

(-8/3)+8=6+(-2/3)(−83)+8=6+(−23)

-8+24=18-2−8+24=18−2

16=1616=16

hence LHS=RHS.

-Sahar.

Jim G.
Jan 30, 2018

x=-2/3x=−23

Explanation:

"distribute the bracket and simplify right side"distribute the bracket and simplify right side

rArr4x+8=6+x⇒4x+8=6+x

"subtract x from both sides"subtract x from both sides

4x-x+8=6cancel(+x)cancel(-x)

rArr3x+8=6

"subtract 8 from both sides"

3xcancel(+8)cancel(-8)=6-8

rArr3x=-2

"divide both sides by 3"

(cancel(3) x)/cancel(3)=(-2)/3

rArrx=-2/3" is the solution"

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