How do you solve 4/(x+2 )*( x^2-4)/(4x-8)?

1 Answer
Oct 19, 2015

4/(x+2 )*( x^2-4)/(4x-8) = color(green)(1

Explanation:

4/(x+2 )*( x^2-4)/(4x-8) = 4/(x+2) X (x^2-2^2)/(4(x-2))

We know that color(blue)(a^2 - b^2 = (a+b)(a-b)

Hence x^2 - 2^2 = (x + 2)(x - 2)

The expression will equal

cancel(4)/cancel((x+2)) X {cancel((x+2))cancel((x-2))}/(cancel(4)cancel((x-2)))

= 1