How do you solve #4(-x-3)-2x=3(-2x+5)-3#?

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Answer 1 · 2017-10-26T16:22:57

Open the brackets
#-4x-12-2x=-6x+15-3#
Make all the variables in one side,
#-4x-2x+6x=12+12#
#0x=24#
#x=24/0#
#x=0#