How do you solve #4(x-8)=2(x-5)#?

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Answer 1 · 2016-10-20T17:39:21

#x=11#

#4(x-8)=2(x-5)#

#4*x-4*8=2*x-2*5#

#4x-32=2x-10#

#4x-2x=-10+32#

#2x=22#

#(cancel(2)x)/cancel(2)=22/2#

#x=11#