How do you solve $40= 6z - 10z$ ?

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Answer 1 · 2017-05-22T22:56:05

See a solution process below:

First, combine the like terms on the right side of the equation by factoring a $z$ out of each term:

$40 = (6 - 10)z$

$40 = -4z$

Now, divide each side of the equation by $color(red)(-4)$ to solve for $z$ while keeping the equation balanced:

$40/color(red)(-4) = (-4z)/color(red)(-4)$

$-10 = (color(red)(cancel(color(black)(-4)))z)/cancel(color(red)(-4))$

$-10 = z$

$z = -10$

How do you solve 40= 6z - 10z40= 6z - 10z?