How do you solve #40= 6z - 10z#?

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Answer 1 · 2017-05-22T22:56:05

See a solution process below:

First, combine the like terms on the right side of the equation by factoring a #z# out of each term:

#40 = (6 - 10)z#

#40 = -4z#

Now, divide each side of the equation by #color(red)(-4)# to solve for #z# while keeping the equation balanced:

#40/color(red)(-4) = (-4z)/color(red)(-4)#

#-10 = (color(red)(cancel(color(black)(-4)))z)/cancel(color(red)(-4))#

#-10 = z#

#z = -10#