How do you solve 40y + 40= 50y + 5040y+40=50y+50?

1 Answer
Jul 15, 2017

See a solution process below:

Explanation:

Step 1) Subtract color(red)(40y)40y and color(blue)(50)50 from each side of the equation to isolate the yy term while keeping the equation balanced:

-color(red)(40y) + 40y + 40 - color(blue)(50) = -color(red)(40y) + 50y + 50 - color(blue)(50)40y+40y+4050=40y+50y+5050

0 - 10 = (-color(red)(40) + 50)y + 0010=(40+50)y+0

-10 = 10y10=10y

Now, divide each side of the equation by color(red)(10)10 to solve for yy while keeping the equation balanced:

-10/color(red)(10) = (10y)/color(red)(10)1010=10y10

-1 = (color(red)(cancel(color(black)(10)))y)/cancel(color(red)(10))

-1 = y

y = -1