How do you solve #48= - 11t + 18+ 2t #?

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Answer 1 · 2018-01-30T14:19:28

See a solution process below:

First, group and combine like terms on the right side of the equation:

#48 = -11t + 2t + 18#

#48 = (-11 + 2)t + 18#

#48 = -9t + 18#

Next, subtract #color(red)(18)# from each side of the equation to isolate the #t# term while keeping the equation balanced:

#48 - color(red)(18) = -9t + 18 - color(red)(18)#

#30 = -9t + 0#

#30 = -9t#

Now, divide each side of the equation by #color(red)(-9)# to solve for #t# while keeping the equation balanced:

#30/color(red)(-9) = (-9t)/color(red)(-9)#

#(3 xx 10)/color(red)(3 xx -3) = (color(red)(cancel(color(black)(-9)))t)/cancel(color(red)(-9))#

#(color(red)(cancel(color(black)(3))) xx 10)/color(red)(color(black)(cancel(color(red)(3))) xx -3) = t#

#10/-3 = t#

#-10/3 = t#

#t = -10/3#