How do you solve #48= 4( j + 2)?#

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Answer 1 · 2017-09-09T01:05:55

See a solution process below:

First, divide each side of the equation by #color(red)(4)# to eliminate the need for parenthesis while keeping the equation balanced:

#48/color(red)(4) = (4(j + 2))/color(red)(4)#

#12 = (color(red)(cancel(color(black)(4)))(j + 2))/cancel(color(red)(4))#

#12 = j + 2#

Now, divide each side of the equation by #color(red)(2)# to solve for #j# while keeping the equation balanced:

#12 - color(red)(2) = j + 2 - color(red)(2)#

#10 = j + 0#

#10 = j#

#j = 10#